According to sources, Blake Lively has accepted that her friendship with Taylor Swift is over and is no longer attempting to reconnect with the pop star.
September 15, 2025: The once-unbreakable friendship between pop superstar Taylor Swift and actress Blake Lively has reportedly come to an end, with sources claiming the two have drifted apart due to Lively’s recent legal issues.
According to reports, Lively has accepted that their long-standing friendship is over, and Swift, who is focused on her personal life with fiancé Travis Kelce, has not responded to Lively’s attempts to reconnect.
The alleged fallout stems from a legal battle involving Lively’s co-star, Justin Baldoni, on the set of their film It Ends with Us. Swift’s name was unexpectedly brought into the lawsuit, reportedly upsetting the singer. While a judge recently ruled that Swift does not have to be deposed in the case, her involvement in the legal drama appears to have been a significant point of contention.
A source close to Lively revealed to the Daily Mail that the usual conversations about Swift’s life, particularly her upcoming wedding to Travis Kelce, have ceased. “This is something that we would’ve talked about in the past…But now, it’s just silence,” the source said. The insider added that there is no longer any question about Lively’s role in the wedding, as “she just won’t be there.”
After multiple unanswered texts, calls, and emails, Lively has reportedly stopped trying to force a reconciliation. A source stated that she feels there is “no reason to contact Swift at this moment” and has chosen to move on, focusing on more important aspects of her life.
Despite the personal strain, Swift’s legal team has maintained that the singer has no real connection to the case. However, her lawyers confirmed that she is prepared to testify if required, emphasizing that she would do so out of a legal obligation rather than personal involvement in the dispute. As this chapter of their friendship reportedly closes, both stars appear to be moving forward on separate paths.